248 ELLIPSES Example Graph the ellipse 4x2 9y2 16x18y11 = 0 What are the center, vertices, and foci?To graph an ellipse, visit the ellipse graphing calculator (choose the "Implicit" option) Enter the information you have and skip unknown values Enter the equation of an ellipse In any form you want `x^24y^2=1`, `x^2/9y^2/16=1`, etc Enter the center ( , ) Enter the first focus ( , ) Enter the second focusFollow 36 views (last 30 days) Show older comments Emil Goh on Vote 0 ⋮ Vote 0 Commented Emil Goh on Accepted Answer Joseph Cheng new to matlap
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Graph (x-4)^2/4+y^2/9=1 brainly
Graph (x-4)^2/4+y^2/9=1 brainly-(NOTE It can be shown using polar coordinates that the slope of the graph as it passes through the origin (twice !) is 1 and 1 Returning to (**), we next have that 1 x 2y 2 = 0 , or y 2 = 1 x 2 Substitute this into the original equation (x 2 y 2) 2 = 2x 22y 2, getting ( x 2 (1 x 2) ) 2 = 2x 22(1 x 2) , 1 = 2x 2 2 2 x 2, 3Textbook solution for Calculus Early Transcendental Functions 7th Edition Ron Larson Chapter 101 Problem 6E We have stepbystep solutions for your textbooks written by Bartleby experts!
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X 2 4 y2 9 z 16 = 1 1Its graph is shown in Figure 123 2We illustrate –nding its traces by –nding the intersection of the ellipsoid with the xyplane, the plane z= 2, and the plane z= 8 Note that the last two planes are parallel to the xyplane Intersection with the xyplane On the xyplane, z= 0 hence the equation of the 73 The conjugate of the hyperbola x 2 a 2 − y 2 b 2 = 1 is x 2 a 2 − y 2 b 2 = − 1 Show that 5 y 2 − x 2 25 = 0 is the conjugate of x 2 − 5 y 2 25 = 0 74 The eccentricity e of a hyperbola is the ratio c a, where c is the distance of a focus from the center and a is the distance of a vertex from the centerName equation of trace in xzplane ;
Graph the ellipse and its foci x^2/9 y^2/4=1 standard forms of ellipse (xh)^2/a^2 (yk)^2/b^2=1 (horizontal major axis),a>b (yk)^2/a^2 (xh)^2/b^2=1 (vertical major axis),a>b given ellipse has horizontal major axis center (0,0) x 2 /4 y 2 /9 = 1 The equation is y 2 /9 x 2 /4 = 1 The standard form of the equation of an ellipse center (h, k) with major and minor axes of lengths 2 2 (y k ) 2 /b 2 = 1 or (x h) 2 /b 2 (y k) 2 /a 2 = 1The vertices and foci lie on the major axis, a and c units, respectively, from the center (h, k ) and the relation between a, bRelated » Graph » Number Line » Examples » Our online expert tutors can answer this problem Get stepbystep solutions from expert tutors as fast as 1530 minutes
Midpoint ( − 4, − 2) 5 Distance √ 7 units;I)Given the equation (x^2)/4 (y^2)/9 = 1 (z^2) Find the traces parallel to the yzplane, that is, set x = k (a) Do we have to put a restriction on the value of k?Dx = " x5 15 − x8 24 # 2 0 = 32 15 − 256 24 = − 128 15 07 Example Evaluate Z π π/2
Ex 8 1 4 Find Area Bounded By Ellipse X2 16 Y2 9 1
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X 2 4 − y 2 9 = 1 y 2 9 For the following exercises, assume an object enters our solar system and we want to graph its path on a coordinate system with the sun at the origin and the xaxis as the axis of symmetry for the object's path Give the equation of the flight path of each object using the given information(e) Below is the graph of z = x2 y2 On the graph of the surface, sketch the traces that you found in parts (a) and (c) For problems 1213, nd an equation of the trace of the surface in the indicated plane Describe the graph of the trace 12 Surface 8x 2 y z2 = 9;Y' x 2 4 y 3 = 2 2x y, and (Equation 1) Thus, the slope of the graph (the slope of the line tangent to the graph) at (1, 1) is Since y'= 4/5 , the slope of the graph is 4/5 and the graph is increasing at the point (1, 1) Now determine the concavity of the graph at (1, 1) Differentiate Equation 1, getting
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Determine the type of conic section represented by the equation and graph it x 2 = 4 y – 8 ( x – 0 ) 2 = 4 ( y – 2 ) y – 2 = 1 ⁄ 4 ( x – 0 ) 2 The graph of this equation is a parabola The vertex is at ( 0, 2 ) The vertical axis is x = 0, which is the yaxisThis calculator will find either the equation of the hyperbola (standard form) from the given parameters or the center, vertices, covertices, foci, asymptotes, focal parameter, eccentricity, linear eccentricity, latus rectum, length of the latus rectum, directrices, (semi)major axis length, (semi)minor axis length, xintercepts, and yintercepts of the entered hyperbolaTranscribed Image Textfrom this Question For the surface x^2/4y^2/9z^2/16 = 1 , give the equations and names of the 2D traces, then name the 3D surface and sketch a graph equation of trace in xyplane ;
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0 votes 1 answer Using integration, find the area of the region bounded by the parabola y^2 = 4x and the circle 4x^2 4y^2 = 9In this example the parametric equations are x = 2t and y = t 2 and we have evaluated t at −2, −15, −1, −05, −025, 0, 025, 05, 15 and 2 We have determined the corresponding values of x and y and plotted these points The diagram shows the result of plotting these pointsAnswer to Find the equations of both tangent lines to the graph of the ellipse {x^2} / 4 {y^2} / 9 = 1 that passes through the point (0, 4) not
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All of the following graphs have the same size and shape as the above curve I am just moving that curve around to show you how it works Example 2 y = x 2 − 2 The only difference with the first graph that I drew (y = x 2) and this one (y = x 2 − 2) is the "minus 2" The "minus 2" means that all the yvalues for the graph need to be movedIf so, what is the necessary restriction? 8E Conic Sections (Exercises) Calculate the distance and midpoint between the given two points 1 Distance 5 units;
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